(x+2)^2+8(x+2)+7=0

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Solution for (x+2)^2+8(x+2)+7=0 equation: 



(x+2)^2+8(x+2)+7=0

We multiply parentheses

(x+2)^2+8x+16+7=0

We add all the numbers together, and all the variables

8x+(x+2)^2+23=0

We move all terms containing x to the left, all other terms to the right

8x+(x+2)^2=-23

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